Is There a Quicker Way to Find All Possible Values of h for fh(a+bx+cx2+dx3)?

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SUMMARY

The discussion centers on finding all possible values of h in the linear transformation defined by fh(a+bx+cx²+dx³) = [a+b+c+hd, b+c; -b-c-hd, hb]. Participants explore the implications of row-reducing the associated matrix and the conditions under which h can take on various values. It is established that h can be any real number, as it is a parameter in the transformation, and the kernel and image of the transformation depend on the specific value of h chosen.

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  • #91
(0,1,-1,1) and (0,1,-1,-1)
 
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  • #92
says said:
(0,1,-1,1) and (0,1,-1,-1)
In the spirit of your previous submissions, why not

span{(0, 1, -1, 0), (0, 0, 0, 1)} ?
 
  • #93
Yes!
I originally though this could be the span:
span{ (0,0,0,1) , (0,1,-1,0) , (0,1,-1,-1) , (0,1,-1,1) }

But then I put each vector into a matrix and row reduced them and got the (0,1,-1,0) and (0,0,0,1) vector.
 
  • #94
There is a second part to this question asking if there are any values of h ∈ R such that fh is not an isomorphism? Not sure if I should ask this in a new post or not. I'm not too sure where to start. I've found this problem extremely difficult.
 
  • #95
says said:
There is a second part to this question asking if there are any values of h ∈ R such that fh is not an isomorphism? Not sure if I should ask this in a new post or not. I'm not too sure where to start. I've found this problem extremely difficult.
Please start a new thread. This one is now at 95 posts. Let's put this one out of its misery...
 

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