Is there a simpler explanation for the equation \omega=\frac{2\pi}{T}=2\pi f?

AI Thread Summary
The discussion clarifies the equivalence of angular velocity (\omega) with the formulas \(\omega = \frac{2\pi}{T} = 2\pi f\), emphasizing their validity in circular motion. Participants highlight that angular velocity relates to time and frequency, where frequency (in hertz) represents revolutions per second. The conversation also touches on the broader application of frequency beyond circular motion, suggesting it can describe repetitive events in various contexts. Ultimately, the participants reach a mutual understanding of the concepts involved. The explanation of these relationships enhances comprehension of angular motion and frequency.
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I saw this on Wikipedia
\omega=\frac{2\pi}{T}=2\pi f = v/r

What I don't understand is \omega= \\ \frac{2\pi}{T}=2\pi f
How can they be equivilant?

Thanks
 
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THINK OF THE CIRCULAR MOVEMENT WITH CONSTANT ANGULAR VELOCITY...It will enlighten you.And a bit of trigonometry +geometry woudln't hurt at all...

Daniel.
 
Let me clarify my question:
How can angular velocity be equivilant to 2pi divided by time in seconds and also equivilant to 2pi x hertz (in seconds obviously)? Isn't frequency dealing with circular motion revolutions per second?
 
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Of course it is.That's what i suggested.
T=\frac{1}{\nu}

T=\frac{2\pi}{\omega}

\omega =2 \pi \nu

All of them are valid for circular motion...And completely equivalent...

WHAT IS ANGULAR VELOCITY...?

Daniel.
 
ya, ya. I wasn't doubting they weren't equivilant. I just didnt understand why. I see it now though. Thanks man.
 
Notice though that the so called "circular motion" which frequency must deal with would rather to be thought of metaphoricly. Circular as in a repeation of a certain entity and motion in the sense of things altering as the function of another variable. We may very well measure the frequency of people taking their dogs out on a walk or the frequency of wagons appearing on a merry go round wheel as the function of the distance along it's rim.
 
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