Thermal State in Relativity Theory: Can It Happen?

In summary, the conversation discusses the possibility of convergence to a thermal state in a system of many neutral particles colliding in a box, as well as the behavior of thermodynamic quantities under Poincare transformations. It is confirmed that a thermal state does exist in the relativistic regime, and that quantities like temperature and internal energy density are defined as scalars in manifestly covariant quantities. The conversation also touches on the role of the one-particle phase-space distribution function in determining macroscopic observables.
  • #1
DaTario
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TL;DR Summary
If hard balls start colliding in such a way that most of them have velocities near c, is it possible to speak of a thermal state in the Maxwell- Bolstzmann sense?
Hi All,

Considering a set of many many small hard balls which start colliding inside a box. The velocities of these balls being mostly greater than c/2. Is it possible, in this case, to speak of convergence to a thermal state in the same sense of ordinary thermodynamics (i.e., using Maxwell-Bolzmann distribution)?
Are there any relativistic corrections for different observers?

Best Regards,
DaTario
 
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  • #4
Thanks to you both.

So it seems to be correct to say that there exists, in the relativistic regime of a system with many many neutral particles, a stationary state (or perhaps an asymptotic state) which can be called the system's thermal state (having thus a given temperature T associated with it). Is it?

Comment: I have read partially these materials and it have become clear that there exists a probability density for ##\gamma##, which depends on the velocity. So the answer to my question above seems to be yes. I am just searching for a confirmation.
 
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  • #5
Yes.
 
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  • #6
Thank you, Orodruin.

In this respect, considering a reference frame S' with velocity v (near c) wrt the lab's reference frame S, when an observer in S' "sees" a typical gas sample whose volume is static in S and have temperature T also in S, does this S' observer measure the same temperature T (although a drift velocity v must be taken out)?

Best wishes
 
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  • #7
That's a very good question, and the issue of the behavior of the thermodynamic quantities under Poincare transformations has been a decade-long debate between eminent physicists. Planck was among the first who worked on it and gave one partially consistent picture. A better solution has been found by Ott.

Nowadays we work with manifestly covariant quantities, i.e., with tensors in Minkowski space (including scalars and vectors and the corresponding fields of course; in QT the proper orthochronous Poincare group is substituted by its covering group which means to substitute ##\mathrm{SL}(2,\mathbb{C})## for the proper orthochronous Lorentz group ##\mathrm{SO}(1,3)^{\uparrow}##, and then also spinors of various kinds are added to the theoretical toolkit).

Today we define (sic!) quantities like temperature, chemical potential, internal energy density, entropy density,... as scalars. As with mass one simply takes over the definitions from non-relativistic physics in the local restframe of the medium. For details see

https://www.physicsforums.com/kbibtex%3Afilter%3Aauthor=van%20Kampen: https://www.physicsforums.com/kbibtex%3Afilter%3Atitle=Relativistic%20thermodynamics%20of%20moving%20systems , https://www.physicsforums.com/kbibtex%3Afilter%3Ajournal=Phys.%20Rev. https://www.physicsforums.com/kbibtex%3Afilter%3Avolume=173(https://www.physicsforums.com/kbibtex%3Afilter%3Anumber=1), https://www.physicsforums.com/kbibtex%3Afilter%3Apages=295, https://www.physicsforums.com/kbibtex%3Afilter%3Ayear=1968
http://dx.doi.org/10.1103/PhysRev.173.295
Everything, of course, derives also from (quantum) statistics and thus (quantum) many-body theory and coarsegraining of the microscopic dynamics to macroscopic observables. In this process the one-particle phase-space distribution function plays an important role (e.g., in the Boltzmann transport equation), and accordingly to the above strategy the phase-space distribution function is a scalar field. For details, see

https://itp.uni-frankfurt.de/~hees/publ/kolkata.pdf
 
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  • #8
Thank you, Vanhees71!
 

1. What is the thermal state in relativity theory?

The thermal state in relativity theory refers to the state of a system where the particles within it have a distribution of velocities that follows the Maxwell-Boltzmann distribution. This distribution is a result of the particles' interactions and is characterized by a temperature.

2. Can a thermal state occur in relativity theory?

Yes, a thermal state can occur in relativity theory. However, it is important to note that relativity theory does not provide a complete description of thermal systems, as it does not take into account quantum effects. Therefore, the thermal state in relativity theory is an approximation that is valid in certain situations.

3. What factors influence the thermal state in relativity theory?

The thermal state in relativity theory is influenced by factors such as the temperature, pressure, and energy density of the system. These factors determine the distribution of velocities of the particles within the system and ultimately determine the thermal state.

4. How is the thermal state related to the concept of entropy?

In relativity theory, the thermal state is related to the concept of entropy through the Boltzmann equation, which describes the relationship between entropy and the number of microstates of a system. The thermal state of a system with a given temperature and energy density corresponds to a specific value of entropy.

5. Can the thermal state in relativity theory lead to violations of the laws of thermodynamics?

No, the thermal state in relativity theory does not lead to violations of the laws of thermodynamics. While relativity theory does not fully account for quantum effects, it still follows the laws of thermodynamics, including the conservation of energy and the increase of entropy over time.

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