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Benomatics
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Is there any algebraic proof for Thevenin's theorem?
Benomatics said:Wikipedia did not provide any algebraic proof, they only provided a statement and an examples, which is not clear
Are you saying you can devise a linear circuit to which Thévenin's Theorem does not apply?Benomatics said:In verifying it i found out that only the voltage across the resistive circuit other than the equivalent circuit remains consistent with the original circuit, but the voltages across the resistors in the equivalent circuit, become inconsistent with the original circuit, hence for very complicated purely resistive circuits, it will be wrong to apply Thevenin, especially with circuits with more than 4 rows and colums of nodes
the point of the thevenin circuit is that the load will see the same voltage and current. The voltage across the equivalent resistor means nothingBenomatics said:I think that's a verification rather than a derivative, in a derivative you assume, you don't have to quote any part of the theorem until you completely derive it. However that was insightful, when i did derive it myself, i did not realize other people have verified it. and its only when you derive it that you will understand the shortcomings of the theorem, it will be very difficult to realize it when you only try verifying it. In verifying it i found out that only the voltage across the resistive circuit other than the equivalent circuit remains consistent with the original circuit, but the voltages across the resistors in the equivalent circuit, become inconsistent with the original circuit, hence for very complicated purely resistive circuits, it will be wrong to apply Thevenin, especially with circuits with more than 4 rows and colums of nodes
Of course, because the circuit topology is different.Benomatics said:but the voltages across the resistors in the equivalent circuit, become inconsistent with the original circuit,
thats not correct. It does find the voltage across the load.Benomatics said:Tnk God you now understand me, i am infact not saying Thevenin is wrong, he was rigt on point with his specifics, but it not that thevenin helps you to find voltage across the load directly, it rather finds another voltage.
vth is not the voltage across the load.Benomatics said:Well you are not getting me, you can only find the voltage across the load after finding Vth but Vth does not represent the voltage across the load according to Thevenin and from my derivation.
Benomatics said:thts true, but i insist that Thevenin's theorem on face of it solves the problem, as you now have to deal with the "equivalence circuit" circuit and the load circuit in series but deep inside it distorts the actual state of the circuit, it deletes the history of the circuit save one. the equivalent circuit
Benomatics said:Well like i said, the title of this thread should have been "the shortcomings of thevenin;s theorem", in truth actually i have derived it myself, without using any quotation from thevenin at any point, but i really wanted to know what people think about Thevenin. And i would like you to solve that question i uploaded using Thevenin
Benomatics said:Find the equivalent circuit for the problem below with R7 as the load below , i am sure you would opt for something else.
I suppose that is arguable but seriously we assume a lot of false states in engineering. As pointed out before, no one cares about what is going on inside the network, only at the port(s).Benomatics said:The theorem might be useful but it actually assumes a false state to solve a problem.
Benomatics said:Sorry i did not complete that, you might think i do not understand Thevenin's theorem, but infact i do and i have derived, it and if you wish to confirm, i have included the document in this post. Thevenin succesfully calculates the voltage across the load, though even for for more complex circuits you will rather opt for other theories. Technically Thevenin;s theorem creates another problem to solve a problem. Changing the circuit just to suit one particular load, but forgetting that you are at the same time rendering the other resistive components inconsistent in regards to properties with the original, for the solution to the problem, i willl get back to you on what i think about it, and i am preparing a different one this time with two or more voltage sources. However i am really enjoying the contribution here.Bye for now.
Benomatics said:Changing the circuit just to suit one particular load, but forgetting that you are at the same time rendering the other resistive components inconsistent in regards to properties with the original, for the solution to the problem