How Is Thevenin Resistance Calculated in R1 Parallel to R2 Configuration?

  • Thread starter Thread starter theycallmevirgo
  • Start date Start date
  • Tags Tags
    Resistance Thevenin
Click For Summary

Discussion Overview

The discussion revolves around the calculation of Thevenin resistance in a circuit configuration where resistor R1 is in parallel with resistor R2. Participants explore the implications of having no load and the conditions under which the resistors are considered in parallel versus series.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions how Thevenin resistance is derived as R_th = R_1 || R_2 when there is no load, suggesting that R1 and R2 should be in series.
  • Another participant proposes that if ground and Vin are treated as having zero impedance, the R1-R2 junction can be viewed as two resistors in parallel.
  • A further clarification indicates that R_th is measured across the R1-R2 junction and the ground/Vin node, supporting the parallel interpretation.
  • It is noted that when considering an ideal voltage source with zero impedance, the ground and Vin can be treated as the same node for calculating Thevenin resistance.
  • In contrast, if an ideal current source is used instead, it is suggested that R_th would only be R2, as the current source would be disconnected due to its infinite impedance.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of the circuit configuration, particularly regarding the conditions under which R1 and R2 are considered in parallel or series. The discussion remains unresolved as there are competing interpretations of the Thevenin resistance calculation.

Contextual Notes

Participants rely on assumptions about the impedance of the voltage source and the configuration of the circuit, which may affect the interpretation of Thevenin resistance. The discussion does not resolve the implications of these assumptions.

theycallmevirgo
Messages
108
Reaction score
25
TL;DR
How is thevenin equivalent calculated for this network
The attached image (Horowitz & Hill Student Manual for 2nd ed) gives thevenin resistance and voltage for the network R_1+(R_2||R_L) as

R_th=R_1||R_2

E_th=E_in(R1/(R_1+R_2)) E_th is self-evident (voltage divider) but how in the world they get R_th i beyond me. If there is no load, isn't R_1 in series with R_2 no matter what?
Capture.JPG


Many thanks in advance

Joe
 
Engineering news on Phys.org
theycallmevirgo said:
If there is no load, isn't R_1 in series with R_2 no matter what?
If you consider the ground and Vin to both have zero impedance, then the impedance of the R1-R2 junction is seen as the two resistors in parallel.
 
  • Like
Likes   Reactions: theycallmevirgo
Baluncore said:
If you consider the ground and Vin to both have zero impedance, then the impedance of the R1-R2 junction is seen as the two resistors in parallel.
So if I understand you correctly, wrt resistance gnd and v are "the same node" and therefore R_t is "measured across" R1-R2 junction and ground/v "node"?
 
Yes.
An ideal voltage source has a zero impedance, so ground Vin when calculating the thevenin resistance of the R1-R2 junction node.

If the supply was instead an ideal current source Iin, you would disconnect it as it would have an infinite impedance, then Rth would be only R2.
 
  • Like
Likes   Reactions: theycallmevirgo

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 34 ·
2
Replies
34
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 11 ·
Replies
11
Views
4K