Is there any quantity in physics that has the unit kg^2 in it?

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The discussion centers around the existence of a physical quantity with the unit kg², with participants noting that no fundamental quantity is recognized in physics with these units. While one can derive kg² from rearranging the gravitational force equation, it lacks practical significance. Observations highlight that mass does not exhibit the same variety of exponents as length and time, suggesting a philosophical distinction in their treatment in physics. The conversation also touches on the relationship between different unit systems, particularly in electromagnetism, and how charge can be derived from force and distance. Ultimately, the participants conclude that while kg² can be mathematically constructed, it does not correspond to any meaningful physical quantity.
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Is there any quantity in physics that has the unit kg^2 in it?
 
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Nothing fundamental exists to my knowledge with those units. You could construct anything you want though. For instance, the Newtonian gravitational force between two bodies of identical mass is F = G r-2 m2. You could rearrange this to be m2 = Fr2/G and both sides now have units of kg2
 
labview1958 said:
Is there any quantity in physics that has the unit kg^2 in it?
Take any physical quantity with units of kg and square it and give it a name. Then you have a physical quantity with units of kg^2.

I don't think that is what you mean, but I don't know what you really want.
 
I'm not aware of any useful quantity with units of kg2
 
labview1958 said:
Is there any quantity in physics that has the unit kg^2 in it?

That's an interesting observation: length and time both occur with many different exponents, but mass does not, apparently.
 
Andy Resnick said:
That's an interesting observation: length and time both occur with many different exponents, but mass does not, apparently.

I'm not sure that exponents of length and time are completlely analogous though.

At least in classical physics, there seems (to me) to be a philosophical difference between an integral over an area or volume, leading to units of L2 or L3, and a double integration or differentiaton wrt time, leading to T2.

To give a specific example, for acceleration necessarily seems to need to be interpreted as (m/s)/s, but it doesn't make much sense to interpret density as ((kg/m)/m)/m.

One might say that space is intrinsically multi-dimensional, but time and mass are not.

And how the "MLT" units for electrical quantites, for example charge = M0.5L1.5T-1, relate to all this is another question!
 
AlephZero said:
And how the "MLT" units for electrical quantites, for example charge = M0.5L1.5T-1, relate to all this is another question!
Could you elaborate on this?
 
AlephZero said:
And how the "MLT" units for electrical quantites, for example charge = M0.5L1.5T-1, relate to all this is another question!

lugita15 said:
Could you elaborate on this?

There is an alternative system of units for electromagnetism, http://en.wikipedia.org/wiki/Gaussian_units" , where Coulomb's law is written without any proportionality constant:
F = \frac{Q_1 Q_2}{r^2} \text{ ,}
i.e. without the factor of k or 1/4πεo. With units of force and distance already defined in mechanical physics, this equation determines the units of charge in much the same way that F=ma sets the units of force to be MLT -2.

Solving the above equation for the charges, we get
Q_1 Q_2 = F \ r^2
So the units of charge2 are equivalent to F·r 2. Or we can say that the units of charge are equivalent to (F·r 2)1/2:
Charge units ~ (MLT -2 · L2)1/2 = (ML3T -2)1/2 = M1/2L3/2T -1
 
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Redbelly98 said:
There is an alternative system of units for electromagnetism, http://en.wikipedia.org/wiki/Gaussian_units" , where Coulomb's law is written without any proportionality constant:
F = \frac{Q_1 Q_2}{r^2} \text{ ,}
i.e. without the factor of k or 1/4πεo. With units of force and distance already defined in mechanical physics, this equation determines the units of charge in much the same way that F=ma sets the units of force to be MLT -2.

Solving the above equation for the charges, we get
Q_1 Q_2 = F \ r^2
So the units of charge2 are equivalent to F·r 2. Or we can say that the units of charge are equivalent to (F·r 2)1/2:
Charge units ~ (MLT -2 · L2)1/2 = (ML3T -2)1/2 = M1/2L3/2T -1
Yes, I already knew about CGS units. I thought you meant there was a way to relate them in SI.
 
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AlephZero said:
I'm not sure that exponents of length and time are completlely analogous though.

<snip>

That's correct- notions of MLT are totally different than x-y-z (or variations thereof: xyzt, MLTQ, etc.).
 

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