Is there such a thing as gravitational pressure?

AI Thread Summary
The discussion revolves around the concept of gravitational pressure, which lacks a rigorous definition and is often misunderstood. The initial inquiry questions the validity of calculating gravitational force per square meter on Earth, leading to absurdly high values. The conversation touches on the relationship between energy and mass in gravitational contexts, particularly referencing photons and their ability to exert pressure, while questioning whether gravitons can do the same. The need for specificity in discussing gravitational pressure is emphasized, as well as the exploration of energy density in gravitational fields. Ultimately, the idea of energy being "stored" in the gravitational field is raised as a point of interest in general relativity.
diagopod
Messages
96
Reaction score
3
I see the term once in a while, but generally not in a rigorously defined context. And when I think in terms of the gravitational force per square meter on the Earth, for example, I'm not sure it's a concept I can grasp, since gravitational force is always defined with respect to a second body. If I write the mass of the earth, times the gravitational acceleration on the Earth's surface, divided by the surface of the earth, I do get a force per square meter or pressure for the Earth's surface, but it seems absurdly high, and I don't think that's a valid approach anyway. Any thoughts on this would be appreciated. Thanks.
 
Physics news on Phys.org
I could be way off the mark on this one, but gravitational pressure may be in reference to pressure caused by graviton particles. In the same way that photons give momentum to a solar sail (through application of a pressure/force over time). Relativistically photons have mass, however I'm not sure if the same could apply to gravitons.
 
It'd be more correct (at least, according to modern conventions) to say that photons have energy, not mass, but also that energy acts just like mass for the purposes of gravity. (In Einstein's equation G_{\mu\nu} = 8\pi T_{\mu\nu}, the tensor on the right side includes both energy and mass)

Anyway, the reason photons are able to exert pressure on something like a solar sail is that they bounce off it, and so in order for momentum to be conserved, the sail has to gain (or lose) some momentum. For the same to be true of gravitons, they'd have to be able to bounce off objects, but I'm not sure I've ever heard whether such a thing is possible.

diagopod, I think in order to get meaningful information about this, you'd have to be more specific about what you mean, or at least where you're seeing the term. I'm not really sure what it might be referring to based just on what you've said here. You're right that just dividing gravitational force by surface area doesn't really tell you anything meaningful.
 
diazona said:
diagopod, I think in order to get meaningful information about this, you'd have to be more specific about what you mean, or at least where you're seeing the term.

Thanks for all your help. Regarding context, I've seen two or three cases in which the "energy density" of the gravitational field is explored, usually as an extrapolation of the well-known equations for energy density of the electrostatic field: U = 1/2(Epsilon0)|E|^2, which would translate to U(g) = 1/2g^2/G8pi, which in turn translates into a pressure. I'll try to find a link and post it, but I found the idea interesting. In GR, is energy "stored" in the field?
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top