JakePearson
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a(a-6) + 9 = 0
a2 - 6a + 9 = 0
(a - 3)(a - 3) = 0
a = -3
is this correct
a2 - 6a + 9 = 0
(a - 3)(a - 3) = 0
a = -3
is this correct
The algebraic expression presented, a(a-6) + 9 = 0, is correctly transformed into a quadratic equation a² - 6a + 9 = 0. The factorization (a - 3)(a - 3) = 0 is accurate, leading to the solution a = 3, not a = -3 as incorrectly stated. The final conclusion is that the correct solution to the equation is a = 3.
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JakePearson said:a(a-6) + 9 = 0
a2 - 6a + 9 = 0
(a - 3)(a - 3) = 0
a = -3
is this correct