Is this how to attempt this problem on electric field strength

[KieranRC]

Homework Statement

Two parallel plates at -50kV and 100kV have separation 35cm. a proton is placed between the plates. calculate the electric field strength between the plates

Homework Equations

E=v/d

The Attempt at a Solution

100kV--50kV=150kV 150x10^3/0.35=428571.4N/C

 

[BvU]

Hello Kieran,

In one word: yes !

(However, since you only get two digits from the voltage, perhaps 420 $\times 10^3\$N/C is a bit cleaner. But by all means: do further calculations with the number you found.)

 

[KieranRC]

Hello Kieran,

In one word: yes !

(However, since you only get two digits from the voltage, perhaps 420 $\times 10^3\$N/C is a bit cleaner. But by all means: do further calculations with the number you found.)

Okay, great! Thank you

The question later goes on to ask what force is experienced by the proton and i really don't know where to start on this one, could you try shed some light on this for me? Thanks

 

[BvU]

For that you need a relevant equation, something like Force = Electric field strength * charge, or $\vec F = q \vec E$. You have the two factors on the right, so: no problemo. But check the direction !