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Is this how to attempt this problem on electric field strength

  • Thread starter KieranRC
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  • #1
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Homework Statement


Two parallel plates at -50kV and 100kV have separation 35cm. a proton is placed between the plates. calculate the electric field strength between the plates

Homework Equations


E=v/d

The Attempt at a Solution


100kV--50kV=150kV 150x10^3/0.35=428571.4N/C
 

Answers and Replies

  • #2
BvU
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Hello Kieran, :welcome:

In one word: yes !

(However, since you only get two digits from the voltage, perhaps 420 ##\times 10^3\ ##N/C is a bit cleaner. But by all means: do further calculations with the number you found.)
 
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  • #3
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Hello Kieran, :welcome:

In one word: yes !

(However, since you only get two digits from the voltage, perhaps 420 ##\times 10^3\ ##N/C is a bit cleaner. But by all means: do further calculations with the number you found.)


Okay, great! Thank you

The question later goes on to ask what force is experienced by the proton and i really dont know where to start on this one, could you try shed some light on this for me? Thanks
 
  • #4
BvU
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For that you need a relevant equation, something like Force = Electric field strength * charge, or ## \vec F = q \vec E##. You have the two factors on the right, so: no problemo. But check the direction !
 

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