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Is this how to attempt this problem on electric field strength

  1. Mar 30, 2016 #1
    1. The problem statement, all variables and given/known data
    Two parallel plates at -50kV and 100kV have separation 35cm. a proton is placed between the plates. calculate the electric field strength between the plates

    2. Relevant equations
    E=v/d

    3. The attempt at a solution
    100kV--50kV=150kV 150x10^3/0.35=428571.4N/C
     
  2. jcsd
  3. Mar 30, 2016 #2

    BvU

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    Hello Kieran, :welcome:

    In one word: yes !

    (However, since you only get two digits from the voltage, perhaps 420 ##\times 10^3\ ##N/C is a bit cleaner. But by all means: do further calculations with the number you found.)
     
  4. Apr 4, 2016 #3


    Okay, great! Thank you

    The question later goes on to ask what force is experienced by the proton and i really dont know where to start on this one, could you try shed some light on this for me? Thanks
     
  5. Apr 4, 2016 #4

    BvU

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    For that you need a relevant equation, something like Force = Electric field strength * charge, or ## \vec F = q \vec E##. You have the two factors on the right, so: no problemo. But check the direction !
     
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