1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric Field Strength Question

  1. Sep 20, 2015 #1
    I already posted this, but it was on the wrong section.
    upload_2015-9-20_16-36-16-png.88944.png
    This is from the 2009 HSC exam. (I'm in Australia)
    I checked the answers and found that electric field strength was
    E = 100/0.10 = 1000V/m
    My question is, what would the electric field strength be if the positively charged plate was +100V instead of 0V
    Would it be 200/0.1 = 2000V/m?
    Is the formula E = The difference in volts between the two plates / distance.
    A person replied and said the two answer are correct

    But another question came up to my mind
    http://www.regentsprep.org/Regents/physics/phys03/aparplate/plate3.gif
    In this gif where
    E = V/d
    Shouldn't it be E = 2V/d
    as there is voltage going to the positive and negatively charged plate for example
    if the battery has 10V
    The negatively charged would be -10V and the positively charge would be 10V
    Then E = 20/d
     
  2. jcsd
  3. Sep 20, 2015 #2

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    If the battery is 10V then it creates a 10V difference. If you want to think of the two voltages as 0 and 10, or -10 and 0, or -5 and +5, it's up to you. They are all equivalent. But it is not -10 and +10 since that would be a 20V difference.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted