Is This Ohm's Law Application Correct for an OP-AMP Circuit?

  • Thread starter Thread starter CoolDude420
  • Start date Start date
  • Tags Tags
    Law Ohm's law
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 2K views
CoolDude420
Messages
199
Reaction score
9

Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

ec61ee1761.png


Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



d66ba13ae1.png
 

Attachments

  • ec61ee1761.png
    ec61ee1761.png
    32.8 KB · Views: 800
  • d66ba13ae1.png
    d66ba13ae1.png
    47.7 KB · Views: 1,001
Physics news on Phys.org
For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?
 
CoolDude420 said:

Homework Statement


Hi,

So I'm just curious whether or not the following statement is correct for the circuit shown. It's part of a bigger problem involving OP-AMPS, the part of the circuit shown is the upper loop connecting from the inverting to the output.

I was just having some doubts in my mind and wanted to confirm whether or not the equation i have written is correct.

View attachment 215789

Homework Equations


Ohms Law. V = IR.

The Attempt at a Solution



View attachment 215790
Interestingly gneill seems to understand your circuit and terminology, but I am struggling with it. However, any way I look at it I can't see the rectangular component as being a capacitor unless the OP AMP in question is a differentiating OP AMP and even then I would need to see a feedback resistor which is a key part of the the various voltage components. Since we are doing V = IR (or in this case I = V/R) I cannot understand this to be differentiating problem, so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies. Also, if this is an integrating OP AMP, then there must be two resistor, R input and R feedback.
I may be just having a dumb day, bit I would like to see a full circuit, with the components correctly defined before I could comment on the correctness of the value terminology used in the equation.
 
Quandry said:
...so I would read that the rectangular component is a resistor with a value of 1/S but I am not able to determine what 'S' signifies.
The 's' is the Laplace domain "frequency" variable/operator (yes, it's both). Reactive components such as inductors and capacitors have impedances in the Laplace domain of the forms:

Inductance L: sL
Capacitance C: 1/(sC)

Laplace transforms are a very handy way to write and solve differential equations using simple algebra.
 
It is a sad day when you don't learn something new:smile: Although vaguely aware of Laplace transformations I have never used them.
For a differentiating OP AMP I would use the formula Iinput = C x dVinput/dt
 
gneill said:
For the given component values it looks okay. Presumably the rectangular component is meant to represent a 1 F capacitor?

Yes! That's exactly what it was meant to be. Thank you