# Is this possible?

#### dontdisturbmycircles

1. Homework Statement
If y'=0 and y=1 when x=2, and y''-4=0, find the function.

2. Homework Equations
$$\frac{dy}{dx}=\int\frac{d^{2}y}{dx^{2}}$$

3. The Attempt at a Solution

I hate posting this because I am pretty sure the solution is easy but I just can't seem to see through this question...

If y'=0 then there must be no x term in the function f(x)... thus y=C is the only possibility. So then y=1 is the only possibility for the initial conditions given.... And if y''=4 then shouldn't y'=4x+C? :/

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Homework Helper
1. Homework Statement
If y'=0 and y=1 when x=2, and y''-4=0, find the function.

2. Homework Equations
$$\frac{dy}{dx}=\int\frac{d^{2}y}{dx^{2}}$$

3. The Attempt at a Solution

I hate posting this because I am pretty sure the solution is easy but I just can't seem to see through this question...

If y'=0 then there must be no x term in the function f(x)... thus y=C is the only possibility. So then y=1 is the only possibility for the initial conditions given.... And if y''=4 then shouldn't y'=4x+C? :/
The boundary values are y(2) = 1 and..? What do you mean by y' = 0? For which x is this true?

#### neutrino

Have you tried solving the equation y" - 4 =0, and then applying the initial conditions?

If y'=0 then there must be no x term in the function f(x)... thus y=C is the only possibility. So then y=1 is the only possibility for the initial conditions given....
Remember, they are not the general expression as a function of x; those are values of the function and its derivative at the point x = 2.

#### cristo

Staff Emeritus
1. Homework Statement
If y'=0 and y=1 when x=2, and y''-4=0, find the function.
These intial conditions are y'(2)=0 and y(2)=1. You have assumed y'=0 for all x.

#### dontdisturbmycircles

Ahhh okay I was misreading the damned question, ... I kinda thought it was worded funny... Trying to breeze through my homework too fast I guess.

Sorry! Thanks all, I get it now :-)