LouisL said:
I am thinking of a copper wire that is used in a basic electrical circuit to light a light bulb.
The wire does not light the bulb. The wire carries electric current. The current lights the bulb
Is the voltage of this wire an inherent property of copper at a given temperature? If not, what factors affect its voltage?
No.
You have a fundamental misconception about voltage (not surprising in view of how books write about it.) In the context of circuit electricity, voltage always refers to the
difference between two points in the circuit. A single wire never has a voltage. A wire can only have a votage compared to another wire. So when you connect two wires to the ends of a 9 V battery, the difference between the wires is 9 V.
The wires simply serve to pass this difference along to the bulb and to carry any current which may (or may not) flow through the ulb.
The voltage difference across the terminals of the bulb, along with a characteristic of the bulb called its resistance, determines how much current can flow through it.
Lets assume there is a battery made of copper wire. Would the electrolyte solution at the anode and cathode affect the voltage? What other factors would affect voltage?
The battery cannot be made of just copper. You already know it also needs an electrolyte. As MJC has pointed out, you also need another different material, such as zinc. Both metals are in contact with the electrolyte and one, in this case zinc, dissolves more energetically than copper. As Zn atoms dissolve to make Zn
++ ions, they leave electrons behind on the metal. The copper also tends to dissolve, but much more lazily!
If the two metals connected with wire in a circuit, the electrons at the zinc end flow through the wire to the copper end, where they actually attract any copper ions back and make them into atoms again. They will also attract hydrogen ions and convert them into atoms.
If the elctrodes are not connected, then a balance is reached between metal dissolving to make +ve ions , leaving -ve electrons behind, and the -ve electrons attracting the +ve ions back to convert them into atoms. As soon as you make a circuit and allow some elctrons to escape from the electrode, there is less -ve attraction and more atoms can dissolve to make ions.
The voltage
difference between the copper and zinc ends, depends on the relative tendency of copper and zinc to dissolve as ions in the electrolyte. Zinc is pretty keen to dissolve, but copper is quite happy as it is.
Would doubling the diameter of the copper wife affect the voltage?
Not in the way you're thinking. Essentially, battery voltage difference depends on the materials of the two electrodes and on the electrolyte. Copper is copper and zinc is zinc, whatever size they are. But if the area of the electrodes are bigger, then there is more opportunity for metal to dissolve and the battery can supply a bigger current. The voltage will still be the same, depending only on the relative tendency for each atom to ionise.
There is a way the thickness of the wires can affect the voltage difference across the bulb. Copper wire is not a perfect conductor, so there is some voltage difference between the ends of a single wire when it is carrying current. Thicker wires need less voltage difference aong their length to make the current flow. So thicker wires mean more of the voltage difference from the battery reaches the bulb.