Is {(x,y)∈R^2 | 2x+y≤2, x-y>4} an Open Subset of R^2?

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SUMMARY

The subset {(x,y)∈R^2 | 2x+y≤2, x-y>4} is determined to be neither open nor closed in R^2. The inequalities can be rearranged to x>2, y≤-2x+1, and y PREREQUISITES

  • Understanding of inequalities in R^2
  • Familiarity with the concepts of open and closed sets in topology
  • Ability to graph linear equations and interpret regions in the Cartesian plane
  • Knowledge of neighborhood definitions in metric spaces
NEXT STEPS
  • Study the definitions of open and closed sets in topology
  • Learn how to graph inequalities in R^2
  • Explore the concept of interior points and their significance in set theory
  • Investigate examples of sets that are open, closed, or neither in R^2
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Mathematicians, students studying topology, and anyone interested in understanding the properties of subsets in R^2.

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1. {(x,y)[itex]\in[/itex] R^2 such that 2x+y<=2, x-y>4} Determine whether this subset of R^2 is open, closed or neither open nor closed.


2. I think this is an open subset but not sure how to prove it. I have rearranged the equations to give x>2, y<=-2x+1, y< x-1. I think it is open because x can get closer and closer to 2 but never equal it and y can get closer and closer to x-1 but never equal it. I'm not sure how prove this mathematically though?

Any help or hints would be great!
 
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First things first. Draw what your set looks like by re-arranging your equations a bit. This will allow you to see whether or not your set is open.

Remember a set is open if every point is an interior point, that is for any point you choose, every neighborhood around it contains points only from the set.
 

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