find the volume under the surface z=(y)(x)^2 and above the triangle with vertices (4,0) (1,0) (2,1)
The Attempt at a Solution
i got my limits of integration to be y=0 to y=1 and x=y+1 to x=4-2y. my integrand itself is (y)(x)^2dxdy
i just wanted to see if this is correct.