Its been a year now i'm backhelp ? =D

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A user returns after a year seeking help with a physics problem involving a racing car's forces. The car has a mass of 1500 kg, accelerates at 5.0 m/s², and experiences lift and ground effects. The discussion emphasizes using the net force equation Fnet = ma, while also considering friction and the normal force related to the car's weight. Participants clarify that the net force in the vertical direction is zero and guide the user to calculate the driving force needed for acceleration, factoring in friction. The conversation aims to assist the user in understanding the physics concepts necessary to solve the problem.
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its been a year now I'm back . help please ? =D

hey guys it's been a while i haven't been on in a long time since last year when i last had physics 10 the introductory course and now I'm back just looking for guidance how to do this question ( helping friend :!) anyways
here it is:

A racing car has a mass of 1500kg, is accelerating at 5.0m/s^2, is experiencing a lift force of 600 N up (due to its streamlined shape) and ground effects of 1000 N down (due to air dams and spoilers). Find the driving force needed to keep the car going given that uk = 1.0 for the car


since it's been so long since I've last done physics the only equation that comes to mind is Fnet = ma but I'm sure that's wrong lol sooo can someone help me out? thanks !
 
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Welcome back.

The equations you have written holds true for any situation. But in this case you may forget that whatever resultant force downward the car provides, will be provided equally in the opposite direction by the ground. So we know there will be NO net force UP or DOWN.

Can you work out the FORCE that is needed to accelerate the car by this much (neglecting friction)?

Now we have to consider friction. There will be a force of friction opposing this force you have worked out now. So we need to increase the force, by adding the magnitude of friction to the previous answer.

Friction = Normal Force x Coefficient of kinetic friction

What is the normal force? (Hint: don't forget about the objects WEIGHT).

Hope this helps,
Sam
 
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