Comp Sci Java Error: "Type Mismatch" Explained

[Niaboc67]

I am programming in Eclipse and I keep seeing the error "
Type mismatch: cannot convert from int to String", not only in the example I am going to provide but other programs. I've just started programming in Java. Could someone explain to me what this error exactly means?
publicclassPracOne{

publicstaticvoidmain(String[] args){String s1 = 8;

String s2 = 8;

System.out.print(s1.equals(s2));

}

}

 

[S.G. Janssens]

I rarely program in Java, but I suppose you would have to surround 8 by double quotes, on both lines. Otherwise the 8 represents an int(eger), not a string.

 

[Mark44]

Please use [ code ] and [ /code ] tags as I have done below.
When you copy/pasted your code, it ended up with many spaces taken out that should be there. I have added them back in for the first couple of lines.

I am programming in Eclipse and I keep seeing the error "
Type mismatch: cannot convert from int to String", not only in the example I am going to provide but other programs. I've just started programming in Java. Could someone explain to me what this error exactly means?

public class PracOne{

   public static void main(String[] args)
   {
      String s1 = 8;
      String s2 = 8;
      System.out.print(s1.equals(s2));
   }
}

I agree with @Krylov. Your two String variables should be initialized with string literals, not int values. Those two lines should look like this:

String s1 = "8";
String s2 = "8";

 

[Niaboc67]

Oh of course. Because only int can be a real number value, right? And when working with the String constructor it has to be characters or something within quotes?

 

[Mark44]

Oh of course. Because only int can be a real number value, right?

Sort of. It can't have any fractional part.

And when working with the String constructor it has to be characters or something within quotes?

Yes

 

[Niaboc67]

Is that always true @Mark44? why does the String Constructor have to be within quotes?

 

[Mark44]

Is that always true @Mark44? why does the String Constructor have to be within quotes?

Is what always true?

A String literal has to be in double quotes. That's how you know it's a string literal. A character literal (such as 'a') is in single quotes. I don't understand what you're asking about a String Constructor. Your code doesn't explicitly use a constructor for the String class.