MHB Jonathan's question at Yahoo Answers ( span ( H ) )

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The discussion revolves around finding the value of "a" for the vector v = [2,−3,4,a] to belong to the span H defined by three vectors. It is established that the rank of the matrix formed by these vectors is 3. For v to be in H, the rank of the augmented matrix must also equal 3, which leads to the condition that the determinant of the matrix must be zero. The determinant is calculated to be 12(9-a), indicating that for v to belong to H, a must equal 9. Thus, the solution concludes that a = 9.
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Here is the question:

Find the value of "a" for which

v= [2,−3,4,a]

is in the set

H=span {[2,1,−3,2],[0,2,−2,−2],[0,0,3,3]} a = ?

Here is a link to the question:

Find the value of "a" for which? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello jonathan,

Clearly
$$\mbox{rank }\begin{bmatrix}{2}&{-1}&{\;\:3}& \;\;2\\{0}&{\;\;2}&{-2}&-2\\{0}&{\;\;0}&{\;\;3}&\;\;3\end{bmatrix}=3$$

Then, $(2,-3,4,a)$ belongs to $H$ if and only if:

$$\mbox{rank }\begin{bmatrix}{2}&{-3}&{\;\:4}& \;\;a\\{2}&{-1}&{\;\:3}& \;\;2\\{0}&{\;\;2}&{-2}&-2\\{0}&{\;\;0}&{\;\;3}&\;\;3\end{bmatrix}=3$$
Equivalently, if and only if
$$\det\;\begin{bmatrix}{2}&{-3}&{\;\:4}& \;\;a\\{2}&{-1}&{\;\:3}& \;\;2\\{0}&{\;\;2}&{-2}&-2\\{0}&{\;\;0}&{\;\;3}&\;\;3\end{bmatrix}=0$$

Easily we verify that the previous determinant is $12(9-a)$ so,

$(2,-3,4,a)$ belongs to $H$ if and only if $a=9$
 
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