Joules required to accelerate 1kg of mass

AI Thread Summary
To accelerate 1 kg of mass from rest to a velocity of 0.866c, the relativistic kinetic energy equation is applied. The calculation shows that the kinetic energy (KE) is derived from the equation KE = [(m0c^2) / √(1-v^2/c^2)] - m0c^2. The attempt at a solution mistakenly simplifies the equation, leading to an incorrect conclusion of 1 Joule. The discussion highlights the importance of correctly handling constants like c^2 in relativistic calculations. Ultimately, the correct application of the formula is crucial for determining the energy required for such acceleration.
ally1h
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Homework Statement


how many joules of energy are required to accelerate 1 kg of mass from rest to a velocity of 0.866c?

I tried the relativistic kinetic energy equation, but I feel like it's totally incorrect.


Homework Equations


KE = [(m0c^2) / √(1-v^2/c^2)] - m0c^2
E = KE + m0c^2



The Attempt at a Solution


KE = [(1 kg*m^2/s^2) / √(1 - (0.866c)^2)] - (1 kg*m^2/s^2)
KE = [(1 kg*m^2/s^2) / √(1 -0.75 m^2/s^2) - (1 kg*m^2/s^2)
KE = [(1 kg*m^2/s^2) / (0.5 m/s)] - (1 kg*m^2/s^2)
KE = 2 kg*m/s - 1 kg*m^2/s^2
KE = 1 J
 
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Hi ally1h! :smile:
ally1h said:
how many joules of energy are required to accelerate 1 kg of mass from rest to a velocity of 0.866c?

KE = [(m0c^2) / √(1-v^2/c^2)] - m0c^2
E = KE + m0c^2

KE = 1 J

one joule! :smile: :smile:

Hint: what happened to your c2? :wink:
 
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