Justify Assumption of Exponential Response to Free Vibration Problem

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TL;DR
Why assume exponential
Consider a free vibration problem of a mass in 1D: inertia, damping, spring, and no forcing function.

We begin by assuming an exponential response.

And then run through all the cases of under, over, critical damping, etc.

I am fully aware of Euler's formula that relates sine/cosine to complex exponential, etc.

But when an analyst first attemps a solution of such a system, there is no a priori knowedge about such issues -- just a posteriori knowledge
of what it leads to.

Can someone justify why we assume a trial exponential response to a free vibration problem?

The only answer I seem able to give is that: it works because Euler, complex, trig, etc.

(Forgive me for marking this "Advanced" I seek a more conceptual understandingFor example, could one say that the derivatives of the exponential are exponential and this serves as a basis for all possible functions?
 
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Trying2Learn said:
For example, could one say that the derivatives of the exponential are exponential and this serves as a basis for all possible functions?
You hit the nail on the head (old dutch expression).

In dealing with differential equations like ##x'' + \omega^2 x = 0## it is sensible to try exponentials. See characteristic equation in calculus books.
 
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You don't need to assume any response. Newton's second law gives you a homogenous second order differential equation, $$m\ddot{x} + b \dot{x} + kx = 0$$ You can solve the complementary equation for ##\lambda## for the three different types of damping (depending on whether the discriminant ##b^2 - 4mk## is less than, equal to, or greater than zero) and come up with the equation of motion.

If you get complex ##\lambda = a \pm bi##, the complementary solution is of the form ##x = Ae^{at}\cos{(bt + \phi)}##. This is the case with underdamping!
 
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OK, you need to know Euler's equation, a priori in your words.
Then the equation given in the previous post is solved in a number of ways. The "classical" way is to assume exponential solutions. Unexplained, a priori!

If you're working towards an electrical degree you will be saved with the use of the Laplace transform. Essentially you just look up the relevand Laplace-transformed term(s) in a nice table to get the time response. SO much easier and it includes all initial conditions FOR FREE! :smile:
 
Trying2Learn said:
(Forgive me for marking this "Advanced" I seek a more conceptual understanding
No. "A" means you have a graduate school background and want to discuss the subject at the graduate school / PhD level. I will change it to "I" for you.
 
Here is a simple but intuitive way of thinking about Euler's equation and oscillations (vibrations):


I suggest watching from the beginning (and also previous lessons).
It's a bit on the basic level, but perhaps you will gain better insights.
 
thank you all. I just logged back in, and saw there were additional comments.
Thank you.
 
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