Kinematics - Can the car avoid the moose

  • Thread starter Thread starter k790
  • Start date Start date
  • Tags Tags
    Car Kinematics
AI Thread Summary
To determine if the car can stop in time to avoid the moose, the distance traveled during the driver's reaction time must be calculated first, which is 8.8 meters at 22 m/s over 0.40 seconds. Next, the stopping distance after braking must be calculated using the deceleration rate of -6.4 m/s², resulting in a stopping distance of approximately 39.6 meters. Adding the reaction distance to the stopping distance gives a total of 48.4 meters, which is less than the 50 meters to the moose, indicating the car will stop in time. If the deceleration is reduced to 4.8 m/s² due to wet conditions, the stopping distance increases, making it likely that the car will not stop in time to avoid the moose. Overall, the calculations show that both the reaction time and braking distance are critical in assessing the ability to avoid the moose.
k790
Messages
1
Reaction score
0

Homework Statement



You are driving along the road at 80 km/h (22m/s) when you see a moose 50.0 m in front of your car. Your reaction time is 0.40 s, and when you finally hit the brakes your car decelerates at a rate of -6.4 m/s2.

a) Will your car stop in time to avoid the moose?

b) If the road is wet and your car decelerates at a rate of 4.8 m/s2, what will happen?

Homework Equations



d = ½( vo + vf) t
at = vf– vo
d = vot + ½ at2
vo2= vf2 + 2ad

The Attempt at a Solution



Ive tried using the equations, I know vi= 22m/s then vo=Om/s but I think I am making some sort of mistake, can someone push me in the right direction?
 
Physics news on Phys.org


You need to calculate how far you will travel during your reaction time, using your distance function. Then calculate how long it will take to stop using your velocity function. Take that time and plug it into your distance function and add the reaction time distance to the stopping distance and see if it's greater than 50 meters.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top