LoveBoy
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When we apply this equation ?
v^2-u^2=kt^2/2m
v^2-u^2=kt^2/2m
Not sure what that equation is supposed to be. It looks like a mash up of these two:LoveBoy said:When we apply this equation ?
v^2-u^2=kt^2/2m
Thanks !Doc Al said:Not sure what that equation is supposed to be. It looks like a mash up of these two:
##x = x_0 + v_0 t + (1/2) a t^2##
##v^2 = v_0^2 + 2 a \Delta x##