Kinematics of rectilinear motion - multiple displacements

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SUMMARY

The discussion focuses on solving a kinematics problem involving a cheetah and an antelope, where the cheetah runs at a maximum speed of 100 km/h and the antelope at 65 km/h. Both animals accelerate to their maximum speeds in 4 seconds and the cheetah catches the antelope in 15 seconds. The key equations for solving the problem include v = u + at, s = ut + 1/2at², and s = 1/2(u + v)t. The correct initial distance between the two animals is determined to be 126 meters.

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derRoboter
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Homework Statement



A cheetah is estimated to be able to run at a maximum speed of 100km.h^1 whilst and antelope can run at a maximum speed of 65km.h^-1. A cheetah at rest sees an antelope at rest and starts running towards it. The antelope immediately starts running away. Both cheetah and antelope are assumed to move with constant acceleration and reach their maximum speeds in 4 seconds. Assuming that both run along the same straight line and that the cheetah catches the antelope in 15 seconds, find the distance between the animals when they first started moving. 2. Equations I have been given
v=u+at
s=ut+1/2at^2
v^2=u^2+2as
s=1/2(u+v)tmisc

I have been staring at this for a good hour now and am yet to come up with the answer which I know to be 126m. How do i find this value using those equations and the data given?

Kind regards, derRoboter
 
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