1. The problem statement, all variables and given/known data A pellet is fired upward with an initial velocity of 25 m/s. At what times in the pellet 25 meters above its fired height 2. Relevant equations S=ut+1/2at^2 I got it down to, Displacement(s)=25m U(initial velocity)=25 m/s and a=acceleration due to gravity -9.81 I got 25=25t+1/2(-9.81)(t^2) then 25=25t+-4.91t^2 and I am stumped 3. The attempt at a solution I tried dividing both sides by 25t, leaving 1/t=-4.91t^2, but I really have no clue. I cant use the quadratic formula and I need 2 times. Any hints would be very nice! Thank you.