- #1
DrPepper
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Homework Statement
A pellet is fired upward with an initial velocity of 25 m/s. At what times in the pellet 25 meters above its fired height
Homework Equations
S=ut+1/2at^2 I got it down to,
Displacement(s)=25m
U(initial velocity)=25 m/s
and a=acceleration due to gravity -9.81
I got 25=25t+1/2(-9.81)(t^2)
then 25=25t+-4.91t^2 and I am stumped
The Attempt at a Solution
I tried dividing both sides by 25t, leaving
1/t=-4.91t^2, but I really have no clue.
I can't use the quadratic formula and I need 2 times. Any hints would be very nice! Thank you.