Kinematics problem(already have the answer, but i need an someone to explain it to me

  • Thread starter Thread starter ihatecats2014
  • Start date Start date
  • Tags Tags
    Explain Kinematics
AI Thread Summary
The problem involves a motorcycle accelerating to catch up with a car traveling at a constant speed. Initially, both vehicles are moving at 48.0 mph with a 60.0 m distance apart. After 5 seconds, the motorcycle accelerates at 7.00 m/s². The key equations used include the kinematic equations for distance and acceleration, leading to the conclusion that it takes 4.14 seconds for the motorcycle to catch up with the car after it begins to accelerate. Understanding the relationship between the distances and speeds of both vehicles is crucial for solving the problem.
ihatecats2014
Messages
30
Reaction score
0

Homework Statement



A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 48.0mph , and the distance between them is 60.0m . After t1 = 5.00s , the motorcycle starts to accelerate at a rate of 7.00m/s^2 . The motorcycle catches up with the car at some time t2

How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car?

the answer is 4.14s

i always seem to have problems with questions that are framed in this way. can someone walk me through the steps? help would be greatly appreciated

oh and these are the equations
x=Vot+1/2at^2
t2-t1
 
Last edited:
Physics news on Phys.org


You can ignore the first part up until t1 = 5s as the distance between the two objects remain 60m.

What happens then is x1 - x2 = 0 where x1 = s1_0 + v1_0*t and x2 = s2_0 + v2_0*t + 1/2*a2*t^2.
(x_1 is not experiencing any acceleration so a1 would be 0)

We also know that s1_0-s2_0 = 60. Also v1_0 = v2_0. After rearranging:
s1_0 - s2_0 + v1_0*t - v2_0*t - 1/2*a2*t^2 = 0
1/2*a2*t^2 = 60.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top