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Q: The average alcohol-free driver requires about 0.8 s to apply the brakes

after seeing an emergency. Calculate the distance travelled after seeing the emergency

before applying the brakes.

with the question, the given speed is 17 m/s and t = 0.8.

at first, i used d =vt equation to find the distance, however,

when i read through the question again, i had a feeling that it's not right.

my first answer was d=14m, but it just doesnt look correct.

i was thinking of finding the acceleration then use v[tex]^{2}_{f}[/tex]=v[tex]^{2}_{i}[/tex] +2a[tex]\Delta[/tex]d

to solve for d, OR, use this equation, [tex]\Delta[/tex]d=1/2(v[tex]_{1}[/tex]+v[tex]_{2}[/tex])[tex]\Delta[/tex]t, without

even having to find the acceleration.

one part of my knowledge tells me that i don't need acceleration to do this question

because this is about "before" applying the break.

its confusing me..

any help would be greatly appreciated.

thank you

after seeing an emergency. Calculate the distance travelled after seeing the emergency

before applying the brakes.

with the question, the given speed is 17 m/s and t = 0.8.

at first, i used d =vt equation to find the distance, however,

when i read through the question again, i had a feeling that it's not right.

my first answer was d=14m, but it just doesnt look correct.

i was thinking of finding the acceleration then use v[tex]^{2}_{f}[/tex]=v[tex]^{2}_{i}[/tex] +2a[tex]\Delta[/tex]d

to solve for d, OR, use this equation, [tex]\Delta[/tex]d=1/2(v[tex]_{1}[/tex]+v[tex]_{2}[/tex])[tex]\Delta[/tex]t, without

even having to find the acceleration.

one part of my knowledge tells me that i don't need acceleration to do this question

because this is about "before" applying the break.

its confusing me..

any help would be greatly appreciated.

thank you

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