- #1
NoobBR
- 3
- 0
Is the equation right ? How do i solve it ?
Thanks in advance and sorry about my poor english or something else
Kinetic energy dissipation by friction
- Thread starter NoobBR
- Start date
Click For Summary
Homework Help Overview
The discussion revolves around the topic of kinetic energy dissipation by friction, specifically focusing on the equations and concepts related to forces and energy balance in the context of motion under friction.
Discussion Character
- Exploratory, Conceptual clarification, Mathematical reasoning
Approaches and Questions Raised
- Participants explore the validity of an initial equation and discuss the distinction between force equations and energy balance equations. There is an attempt to relate the problem to kinematics and the effects of friction on motion, including considerations of constant retardation and nonlinear friction coefficients.
Discussion Status
The discussion is active, with participants providing insights into the nature of the problem and suggesting different approaches, such as solving for acceleration and formulating differential equations. There is acknowledgment of the need to clarify the problem setup and the role of friction.
Contextual Notes
Participants are grappling with the implications of a nonlinear friction coefficient, which adds complexity to the problem. There is a mention of constraints related to the formulation of the problem and the assumptions made regarding the nature of friction.
Is the equation right ? How do i solve it ?
Thanks in advance and sorry about my poor english or something else
- #2
Doc Al
Mentor
- 45,583
- 2,458
Not really. That's not a force equation, but an energy balance one. By setting up such an energy balance equation, you could solve for the distance traveled. But that's not what's asked for.NoobBR said:
Instead, solve for the acceleration.
What's the force of friction?
- #3
vivekrai
- 72
- 0
It is infact just a Kinematics 1D Problem. The body undergoes a constant retardation due to friction. So just use v = u + at .
- #4
NoobBR
- 3
- 0
hmm i formulated wrong. If the friction coeficient "u" is a nonlinear function, let's say, u = x^2 how it would be solved ?
- #5
vivekrai
- 72
- 0
Write force equation and solve the differential Equation.
We'll have [itex]m\cdot \frac{dv}{dt} = \mu mg \implies v dv =k x^2g dx[/itex], Since [itex]\mu = kx^2[/itex]
We'll have [itex]m\cdot \frac{dv}{dt} = \mu mg \implies v dv =k x^2g dx[/itex], Since [itex]\mu = kx^2[/itex]
- #6
NoobBR
- 3
- 0
Thank you very much for the help, you people are right and its a question about aceleration.
Greetz!
Greetz!