Calculating Kinetic Energy with P=1/2Aρv3

AI Thread Summary
The formula P = 1/2 Aρv^3 is used to calculate power, where P is indeed in watts. The variables represent area (A in m²), density (ρ in kg/m³), and velocity (v in m/s). A participant confirmed that using metric units is essential for accurate calculations. The original poster, Rick, initially used non-metric units but acknowledged the need to convert them. Ensuring proper unit conversion is crucial for correct kinetic energy calculations.
rickeeee
Messages
2
Reaction score
0
Hi Everyone,
This is a real simple question, but I should make sure I have this right. In the following formula, is the value of P in watts?

P = 1/2 Aρv3

I'm assuming that this is in watts, but you know what they say about assuming. Thanks in advance for your help!
Cheers,
Rick
 
Physics news on Phys.org
Assuming ρ is in [kg/m3] and v is in [m/s] and A is in [m2], then yes P is in watts.
 
Hello MrMatt,
Thank you very much, I was using Slugs for ρ and A was equal to FT2, but I can convert them to metrics. Glad I double checked!
Cheers,
Rick
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top