Kinetic Energy of Ion accelerated across potential difference

AI Thread Summary
An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 volts. The potential difference transfers energy of 277 eV per unit charge to the ion. To find the final kinetic energy, the charge of the ion is multiplied by the potential difference and added to the initial kinetic energy. This calculation determines the new kinetic energy after acceleration. The discussion emphasizes the relationship between potential difference and kinetic energy in ion acceleration.
iuchem16
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An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?
 
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Hi iuchem16! Welcome to PF! :smile:
iuchem16 said:
An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?

What is the definition of potential difference, and its relation to potential energy ? :wink:

Show us what you've tried. :smile:
 
A potential difference of 277 volts will transfer energy of 277 ev per unit charge to the ion.

Take the charge of your ion, multiply by 277 ev, add to 9.88...
 
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