Kinetic, potential and mechanical energy question.

[solarwind]

Homework Statement

A 5.5 x 10^4 kg airplane, traveling at an altitude of 9.9 km, has a speed of 260 m/s relative to the ground. Nearing the end of the flight, the plane slows to a speed of 140 m/s while descending to an altitude of 2.1 km. Determine the plane's total loss of mechanical energy during this change of speed and altitude.

Homework Equations

E_g = mgh
E_k = \frac{1}{2}mv^2

The Attempt at a Solution

I have no idea how to start to solve this problem. If someone could point me in the right direction, it would be great.

 

[Doc Al]

The mechanical energy is just the sum of gravitational PE and kinetic energy. You have the formulas for both--just crank it out.

 

[solarwind]

The mechanical energy is just the sum of gravitational PE and kinetic energy. You have the formulas for both--just crank it out.

Thanks dude!

 

[solarwind]

Ok, I did this:

a)
Eg = mgh
Ek = mv^2, where v I put 260 m/s
Et1 = Eg + Ek

b)
Same thing as above but with the second values.
Elost = Et1 - Et2.

The answer is supposed tob e 5.5 x 10^9 Joules but i get 4.98 x 10^9 Joules. What did I do wrong? Did I go about this the right way?

 

[Doc Al]

Looks like the right way to me. If you post the details of your calculation, perhaps we can spot an error. (Or confirm your answer.)