Kinetic Temperaturea and molecular velocities

  • Context: Graduate 
  • Thread starter Thread starter mrcotton
  • Start date Start date
  • Tags Tags
    Kinetic Molecular
Click For Summary
SUMMARY

At the triple point of water (273.16 K), the chemical potentials of ice, water, and vapor are equal, not the average kinetic energies of the particles. While temperature is defined as the average kinetic energy (KE) of particles, the mean squared speeds of molecules in different states (liquid and gas) can be the same at this temperature due to the relationship defined by the equation KE = 3/2 kT. This indicates that the translational mean squared speeds of water and vapor can be equal at the same temperature, despite differences in their states.

PREREQUISITES
  • Understanding of the triple point concept in thermodynamics
  • Familiarity with the relationship between temperature and kinetic energy
  • Knowledge of chemical potential and its significance in phase equilibrium
  • Basic grasp of molecular motion and states of matter
NEXT STEPS
  • Research the concept of chemical potential in thermodynamics
  • Study the kinetic theory of gases and its implications for different states of matter
  • Explore the mathematical derivation of the average kinetic energy equation KE = 3/2 kT
  • Investigate the implications of phase changes on molecular velocities and energy
USEFUL FOR

Students and professionals in physics, chemistry, and engineering, particularly those interested in thermodynamics and phase transitions.

mrcotton
Messages
120
Reaction score
0
If I have ice, water and vapour at the triple point and they are in equilibrium at a temperature of 273.16. Does this mean that the average kinetic energy of the particles is the same in each state? If so how can the molecules in the water be moving with the same mean squared speed as the molecules in the vapour? Thanks for any help
 
Last edited:
Science news on Phys.org
At the triple point, it is not he kinetic energies which are equal, but the chemical potentials ##\mu## of the 3 phases of matter.
 
Thanks for responding Matterwave

LatentHeat1_zps76e36554.jpg


Where this question has come from is a discussion I was having about temperature increase as water changes from the solid to the gaseous state. As the water changes from D to E, If temperature is defined as average KE =3/2kT does this imply that the KE and hence the translational mean squared speeds of the liquid at D and the gas at E are the same if they are at the same temperature?
 
Does kinetic temperature real because of molecular moving?
Hint: something else moving?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K