Kinetic Temperaturea and molecular velocities

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At the triple point of water, the average kinetic energy of particles in ice, water, and vapor is not the same; rather, it is the chemical potentials of the three phases that are equal. While temperature is defined in terms of average kinetic energy, the mean squared speeds of liquid water and water vapor can differ despite being at the same temperature. The discussion highlights the complexity of kinetic temperature and molecular motion during phase transitions. As water transitions from solid to gas, the relationship between temperature and kinetic energy becomes nuanced. Understanding these principles is essential for grasping the behavior of matter across different states.
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If I have ice, water and vapour at the triple point and they are in equilibrium at a temperature of 273.16. Does this mean that the average kinetic energy of the particles is the same in each state? If so how can the molecules in the water be moving with the same mean squared speed as the molecules in the vapour? Thanks for any help
 
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At the triple point, it is not he kinetic energies which are equal, but the chemical potentials ##\mu## of the 3 phases of matter.
 
Thanks for responding Matterwave

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Where this question has come from is a discussion I was having about temperature increase as water changes from the solid to the gaseous state. As the water changes from D to E, If temperature is defined as average KE =3/2kT does this imply that the KE and hence the translational mean squared speeds of the liquid at D and the gas at E are the same if they are at the same temperature?
 
Does kinetic temperature real because of molecular moving?
Hint: something else moving?
 
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