KVL loop: Example wrong, or did I misunderstand?

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    Example Kvl Loop
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The discussion centers on a misunderstanding of a KVL loop example from a circuit analysis textbook involving three voltages: -8V, 12V, and an unknown voltage Vr2. The textbook states that Vr2 equals 4V, but the user calculates it as 20V based on their interpretation of the equation. They express confusion over the treatment of the -8V voltage source and seek clarification on its role in the loop. The user suggests that a circuit diagram would aid in resolving the misunderstanding, indicating that one voltage is a source while the others are voltage drops across resistors. Clarification on the treatment of negative voltages in KVL is necessary for accurate analysis.
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In my circuit analysis textbook, there is an example problem using a KVL loop. Though it seems relatively simple, I cannot understand the answer.

the loop consists of 3 voltages: -8, 12, and the unknown, Vr2. The polarities (clockwise) around the loop are respectively +,-,+.

The answer given is 4V for Vr2. I can see this being the case if the 8 wasn't negative, but if I apply algebra, the equation comes out as:

+ (-8) - (12) + Vr2 = 0

where Vr2 = 20

Am I treating the -8 wrong? Because if it were positive 8, I could understand Vr2 being 4, however, I am given to understand negative voltage is different from positive voltage.
 
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A circuit diagram would be helpful.
 
One of those is a voltage source while the other two are the volt drops over resistances huh?
 
Post the circuit diagram otherwise we are guessing what might be wrong.
 

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