Lambert W Function: Solving Y=xe^(x^2)

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SUMMARY

The discussion focuses on solving the equation Y=x exp(x^2) using the Lambert W function. The user substitutes u=x^2 to transform the equation into Y=√u exp(u), leading to the equation 2Y^2=2u exp(2u). By applying the Lambert W function, the user derives that 2u=W(2Y^2), from which the value of x can be determined. This method effectively utilizes the properties of the Lambert W function to solve complex exponential equations.

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Dear scholars,

I am working on the following equation and wonder whether my solution is correct. The actual problem is more complex but the example below captures the main features. I have not a lot of experience with the Lambert W function. Thanks in advance for your comments!

Equation:
$$Y=x \exp(x^2)$$

Substitute: $$u=x^2$$

Then:
$$Y=\sqrt{u} \exp(u)$$
$$Y^2=u \exp(2u)$$
$$2Y^2=2u \exp(2u)$$

Then using W function:
$$2u=W(2Y^2)$$
From which $$x$$ follows.
 
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Correct.
 
Yes, very good!
 

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