Laminar flow in a tube, heat transfer coefficient-sanity check

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SUMMARY

The discussion confirms that the heat transfer coefficient for laminar flow in a tube is virtually independent of the tube diameter. The relationship is established through the Nusselt number, which is weakly dependent on diameter during the developing flow phase. The analysis indicates that for a sufficiently large furnace, the heat transfer rate remains consistent regardless of the tube size. This conclusion is supported by dimensional analysis of the heat balance equation, which shows that the dimensionless temperature is a function of axial position and radius, independent of diameter.

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gpsimms
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Hi there,

Hopefully this is a very easy question and you all can just confirm this for me.

When calculating heat transfer into a fluid from a heated tube, is it correct to say that the heat transfer coefficient is *not* dependent on the tube diameter?

upload_2018-8-7_18-42-39.png


So, if we solve for T_{out}, we get:

upload_2018-8-7_18-45-32.png

Substituting h for K*N/D, which is fluid thermal conductivity K, Nusselt number (depends on flow conditions and location in flow), and D is diameter, we get:

upload_2018-8-7_18-47-58.png

Finally, for our circular duct, A = pi*D*dx, so we get:

upload_2018-8-7_18-49-52.png


So, is there no dependence on tube diameter? I know that Nusselt number is *weakly* dependent on diameter when the flow is still developing, but that seems like it. In other words, given a large enough furnace, I could put a tube of any size in that furnace, and the flow would heat just as quickly regardless of tube diameter. That feels wrong to me, is there something I am missing?

Thanks!
 

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For laminar flow in a tube (with constant wall temperature), what is the equation for the local Nussult number as a function of the Reynolds number, Prantdl number, and x/D in the thermal entrance region?

For laminar flow in a tube (with constant wall temperature), what is the equation for asymptotic Nussult number at large distances along the tube?
 
As best as I can tell, your assessment is correct. For laminar flow, Nu is virtually independent of D.
 
Dimensional analysis of the partial differential heat balance equation shows that the dimensionless temperature ##\frac{T-T_0}{T_w-T_0}## is a function only of the dimensionless axial position ##\frac{kz}{WC_p}## and the dimensionless radius r/R. The dimensionless axial position is independent of diameter.
 
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Yup. After sleeping on it, I felt pretty correct about what I had written. But it is nice to have had someone else look it over. Thank you for your time!

Go Blue!

'06 School of Education
 
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