How to Find the Laplace Transform of cos(t) * f(t)?

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To find the Laplace Transform of cos(t) * f(t), it is essential to recognize that the multiplication of cos(t) and f(t) can be approached by expressing cos(t) as exponential functions. This method allows for treating f(t) as a general function, where the impact of cos(t) is understood as time-shifting. The convolution theorem indicates that the Laplace transform of a product results in the convolution of the individual transforms, although this may not be directly applicable. Ultimately, using the given Laplace Transform F(s) and applying the time-shifting property simplifies the calculation. Understanding these concepts facilitates the transformation process without needing to perform integration by hand.
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I am given a function f(t) with it's corresponding Laplace Transform in the Frequency Domain (F(s)).

I'm having a hard time wrapping my head around the product of say, L{cos(t)*f(t)}. The * is multiplication and not convolution. Must I do the integration for the Laplace transform by hand, or is there a short cut method using the table of Laplace transforms?

I want hints/direction, not a definitive answer.

Thanks
 
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The convolution theorem works both ways; the Laplace transform of a product is the convolution of the Laplace transforms of the multiplicands. This may not be particularly useful to you though.

For cos(t)f(t) in particular, you might try expressing the cosine in terms of exponential functions.

It may be worth noting that cos(t)f(t) is the "double-sideband suppressed-carrier" form of amplitude modulation.
 
Thanks for the response. After mulling it over, I've figured it out:

One must treat f(t) in cos(t) * f(t) as simply any function (it doesn't matter what it is). After converting the cos(t) to exponentials (through) identities, one realizes that cos(t) affects f(t) through time-shifting. With the given F(s) function, one can easily calculate the time shift.

Thanks again
 
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