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Laplace transform using the basic integral

  1. Mar 9, 2009 #1
    The question:

    Find the Laplace transform of f(t)=[tex]te^2^t[/tex]

    I have got:
    IMG_2516.jpg

    Though, this will not become f(s) = 1/(s+2)^2

    Anyone got an idea about what I am doing wrong?
     
  2. jcsd
  3. Mar 9, 2009 #2

    Tom Mattson

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    Staff Emeritus
    Science Advisor
    Gold Member

    That's good because it's not supposed to become that! The answer is:

    [tex]\mathcal{L}\left[te^{2t}\right]=\frac{1}{(s-2)^2}[/tex]

    This is exactly what you have.
     
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