# Laplace transform using the basic integral

#### Pietair

The question:

Find the Laplace transform of f(t)=$$te^2^t$$

I have got:

Though, this will not become f(s) = 1/(s+2)^2

Anyone got an idea about what I am doing wrong?

#### Tom Mattson

Staff Emeritus
Gold Member
Though, this will not become f(s) = 1/(s+2)^2
That's good because it's not supposed to become that! The answer is:

$$\mathcal{L}\left[te^{2t}\right]=\frac{1}{(s-2)^2}$$

This is exactly what you have.

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