Laplace transform using the basic integral

The question:

Find the Laplace transform of f(t)=[tex]te^2^t[/tex]

I have got:
IMG_2516.jpg


Though, this will not become f(s) = 1/(s+2)^2

Anyone got an idea about what I am doing wrong?
 

Tom Mattson

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Though, this will not become f(s) = 1/(s+2)^2
That's good because it's not supposed to become that! The answer is:

[tex]\mathcal{L}\left[te^{2t}\right]=\frac{1}{(s-2)^2}[/tex]

This is exactly what you have.
 

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