- #1
cas159
- 5
- 0
Y' + 8y = e^-2t*sint, with initial condition y(0) = 0
Alright so I've been working on this one for about an hour, I really don't know why but I'm having major problems with these types of problems, whether i don't understand how to set it up or I don't understand partial fraction decomposition, I do not know, but this is what I have done.
(For reference, L{function} is the notation I will use).
L{y''} + 8L{y} = L{e^(-2t)*sin(t)}
sY(s) - y(0) + 8Y(s) = 1/((s+2)² + 1)
1/((s+2)² + 1) = 1/(s²+4s+5)
(s+8)Y(s) = 1/(s²+4s+5)
Y(s) = 1/((s²+4s+5)(s+8))
Now setting up my Partial Fraction Decomposition
As+B/(s²+4s+5) + C/(s+8) = 1/((s²+4s+5)(s+8))
As² + Bs + 8As + 8B + Cs² + 4Cs + 5c = 1
(A+C)s² + (8A + B + 4C)s + 8B + 5C = 1
Setting up my equations:
A + 0B + C = 0
8A + B + 4C = 0
0A + 8B + 5C = 1
I'm getting that A = -1/37, B = 4/37, and C = 1/37, the rest I can do, but the book says that B should be 6/37, can anyone figure out what I did improperly, I would really appreciate it.
Alright so I've been working on this one for about an hour, I really don't know why but I'm having major problems with these types of problems, whether i don't understand how to set it up or I don't understand partial fraction decomposition, I do not know, but this is what I have done.
(For reference, L{function} is the notation I will use).
L{y''} + 8L{y} = L{e^(-2t)*sin(t)}
sY(s) - y(0) + 8Y(s) = 1/((s+2)² + 1)
1/((s+2)² + 1) = 1/(s²+4s+5)
(s+8)Y(s) = 1/(s²+4s+5)
Y(s) = 1/((s²+4s+5)(s+8))
Now setting up my Partial Fraction Decomposition
As+B/(s²+4s+5) + C/(s+8) = 1/((s²+4s+5)(s+8))
As² + Bs + 8As + 8B + Cs² + 4Cs + 5c = 1
(A+C)s² + (8A + B + 4C)s + 8B + 5C = 1
Setting up my equations:
A + 0B + C = 0
8A + B + 4C = 0
0A + 8B + 5C = 1
I'm getting that A = -1/37, B = 4/37, and C = 1/37, the rest I can do, but the book says that B should be 6/37, can anyone figure out what I did improperly, I would really appreciate it.