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## Homework Statement

Taking the transform:

Just wondering, can someone explain to me why the e

^{-3s}/s is positive, and not negative because it is originally -u

_{3}(t)...

Another quick one:

Write this in terms of Heaviside function:

f(t) =

{ 0, 0 <= t <= pi

{ -sin3t, t >= pi

1) So you would get f(t) = -(u

_{pi}t)sin3t

And somehow it ends up as f(t) = (u

_{pi}t)sin(3(t-pi))

Can someone explain this step as well? Just what happened to the negative in front of it, and why it became 3(t-pi)

Thanks!