Hey guys! I just have a question regarding some notes I've been looking at and trying to understand...(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

Taking the transform:

Just wondering, can someone explain to me why the e^{-3s}/s is positive, and not negative because it is originally -u_{3}(t)...

Another quick one:

Write this in terms of Heaviside function:

f(t) =

{ 0, 0 <= t <= pi

{ -sin3t, t >= pi

1) So you would get f(t) = -(u_{pi}t)sin3t

And somehow it ends up as f(t) = (u_{pi}t)sin(3(t-pi))

Can someone explain this step as well? Just what happened to the negative in front of it, and why it became 3(t-pi)

Thanks!

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# Homework Help: Laplace transforms, heaviside step functions

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