1. The problem statement, all variables and given/known data . In the following transient circuit, assume at t<0, the circuit is at steady state. Find v0(t) for t>0 http://sphotos-b.xx.fbcdn.net/hphotos-ash3/c0.0.354.354/p403x403/546839_509413575744829_42997155_n.jpg [Broken] 2. Relevant equations 3. The attempt at a solution The first thing that I was suggested to do was to always find iL(t) so since we have 2 source of voltage. I will be using superposition method. First let use the 12V source only Req for the circuit will be: (2||6) + (3+1||3) Use Req to find the current source due to the 12V and by using current divider rule we can obtain iL(0-) then move on to the 3V source at this point, I am having trouble, so when we short out the 12V, will the current just go through the wire where the 12V used to be and skip the right side of the circuit? but if it is so then iL(0-) for this source will be 0?, which doesn't seem right to me. ok, assume that we actually figured out the value for iL(0-) then to find iL(∞) we only have to deal with the right side of the circuit. so iL(∞) will be equal to the current going through the 1Ω ? and Rth for t>0 will be 3+(1||3) this can be use to find time constant. so suppose we got our equation for iL(t) to find Vo(t) we can try to find io(t) from current divider rule iL(t)= io(t) X (3/4) and once io(t) is obtained, we multiply that by 3Ω to get Vo(t) thanks for your time.