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## Homework Statement

. In the following transient circuit, assume at t<0, the circuit is at steady state.

Find v0(t) for t>0

http://sphotos-b.xx.fbcdn.net/hphotos-ash3/c0.0.354.354/p403x403/546839_509413575744829_42997155_n.jpg [Broken]

## Homework Equations

## The Attempt at a Solution

The first thing that I was suggested to do was to always find i

_{L}(t)

so since we have 2 source of voltage. I will be using superposition method.

First let use the 12V source only

R

_{eq}for the circuit will be: (2||6) + (3+1||3)

Use R

_{eq}to find the current source due to the 12V and by using current divider rule we can obtain i

_{L}(0

^{-})

then move on to the 3V source

at this point, I am having trouble, so when we short out the 12V,

**will the current just go through the wire where the 12V used to be and skip the right side of the circuit?**

but if it is so then i

_{L}(0

^{-}) for this source will be 0?, which doesn't seem right to me.

ok, assume that we actually figured out the value for i

_{L}(0

^{-}) then to find i

_{L}(∞) we only have to deal with the right side of the circuit.

so

**i**

_{L}(∞) will be equal to the current going through the 1Ω ?and R

_{th}for t>0 will be 3+(1||3) this can be use to find time constant.

so suppose we got our equation for i

_{L}(t)

to find V

_{o}(t) we can try to find i

_{o}(t) from current divider rule

i

_{L}(t)= i

_{o}(t) X (3/4)

and once i

_{o}(t) is obtained, we multiply that by 3Ω to get V

_{o}(t)

thanks for your time.

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