Hi, I have a question about LC series oscillators. Specifically when a DC supply is applied. Solving the differential equation for such circuit using as initial conditions at t=0 that Vc=0 and I=0 I get as a solution that the circuit oscillates and the voltage across the capacitor has an amplitude of 2*Vdc. Solution is: Vdc*(1-cos (t/sqrt (LC)) This is also confirmed using Pspice simulation. Now my doubt is that if I consider the circuit impedance j (ωL -1/ωC) of course for ω=0 it goes to infinite which means that with a step signal applied to the curcuit (starting from zero state at t=0) after a transient I should get zero current in steady state. The circuit is not an oscillator but acts like an open circuit in steady conditions according to circuit analysis theory. So what's happening? Thanks.