Learn How to Derive Gauss and Stokes Theorems for Vector Analysis"

AI Thread Summary
The discussion focuses on deriving Gauss and Stokes theorems for a specific vector field and calculating the flux through a defined surface. Participants clarify that Gauss' theorem relates to divergence in R2, while Stokes' theorem applies to surfaces in R3. For the flux calculation, the curl of the vector field is determined, and the projection onto the xy-plane is explained as a method to simplify integration over surfaces. There is a consensus that the first problem requires deriving the theorems under the condition that A is a constant vector, which simplifies the process. Overall, the conversation emphasizes understanding the application of these theorems in vector analysis.
galipop
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Hi All,

I got a couple questions that I need some help getting started on. Any tips would be appreciated.

1. Derive Gauss and Stokes theorems for the field B = Ap(r), where A is a constant vecotr and p (rho)is a scalar field. r is the unit vector.

2. Compute the flux of the field A(r)=(y^2, 2xy, 3z^2-x^2) through the surface of a rectangle defined by the four points (b,a,0) (0,a,0) (0,0,a) (b,0,a)


Thanks
 
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galipop said:
Hi All,

I got a couple questions that I need some help getting started on. Any tips would be appreciated.

1. Derive Gauss and Stokes theorems for the field B = Ap(r), where A is a constant vecotr and p (rho)is a scalar field. r is the unit vector.

2. Compute the flux of the field A(r)=(y^2, 2xy, 3z^2-x^2) through the surface of a rectangle defined by the four points (b,a,0) (0,a,0) (0,0,a) (b,0,a)


Thanks

Gauss' theorem, also called the divergence theorem,(in the form in which I am looking at it now) says that, if P and Q are scalar functions on R2, then \int\int_\Omega \(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\)dxdy= \integral Pdx+ Qdy where the second integral is over the boundary of Ω
Stokes theorem says essentially the same thing except that instead of being in R2, Ω is now some surface in R3.
I'm not sure why you have reference to "r" and "rho". In problem two, you appear to be using "r" to represent the general (x,y,z) vector but surely you are not asking for a general proof of these thwo theorems?

Number 2 is not too hard. You are given that A= (y2,2xy, 3z2-x2). Its curl is <0, 2x, 0>.
The equation of the plane described is y+ z= a. Projecting into the xy-plane, we have ndS= <0, 1, 1> dxdy so curl A.n dS= 4x dx dy. The double integral has limits x=0 to x= b, y= 0 to y= a. The integral is simply (2b)(a)= 2ab.
 
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I'm baffled by question 1 also...as for question 2 I overlooked determining the equation of the plane.

Thanks for your help.
 
Could you explain the part about projecting onto the xy plane for me. I'm not sure why or how you did it.
 
By the way, I calculated the curl to be <0,2x,0>

How does that sound?
 
galipop said:
Could you explain the part about projecting onto the xy plane for me. I'm not sure why or how you did it.

Since you are integrating over a surface, in order to reduce it to terms of 2 parameters so you need to project to one of the coordinate surfaces (you could write the plane in terms of two parametric equations but then calculating the differential would be harder).
Think of a surface as given by f(x,y,z)= constant. Then it is a "level surface" for f and grad f is normal to the surface (at each point). It is easy to show that the length of grad f is the differential of area of the surface and I prefer to think of grad f as being the "vector" differential of area. In order to write the integral in x,y,z, "project" down to the xy-plane by dividing the vector by the z component (so that the z component becomes 1). Alternatively, you can project to the yz-plane or xz-plane. Then integrate over the figure in the plane that the surface projects to.

In this problem, we can write the surface as y+z= a with f(x,y,z)= y+z. Then grad f= <0, 1, 1> . Since the z coordinate is already 1, projecting to the xy plane, dS= <0, 1, 1> dxdy. (Since the y coordinate is already 1, we could project onto the xz plane as dS= <0, 1, 1>dxdz. Since the x coordinate is 0, we could not project to the yz plane- the projection in that direction reduces to a single line.)

galipop said:
By the way, I calculated the curl to be <0,2x,0>

How does that sound?

Yes! I don't why I gave <-2x,2x,-2x>! I went back and calculated it again and it is <0, 2x, 0>.

The integral \int_{x=0}^b\int_{y=0}^a 2x dxdy= ab<sup>2</sup>.
 
Thanks. It all makes sense now.

Cheers.
 
I'm trying to do the same Question as Galipop,

and while I have managed to do question 2 he posted I haven't gotton Question One yet.

Any idea how to derive Gauss and stokes for that field?

It seems to want us to derive the theorems rather than proove them
 
Anyone? Please?
 
  • #10
Okay our lecturer said that we should try to simplify both theorems when A is a constant vector, not a function of space coordinate r=(x,y,z)).

Does that help someone to work out how do do this question, if someone could show me how to do it I would be very happy
 
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