LED States in Current and Reverse Bias Circuit

AI Thread Summary
In the discussion about the LED states in current and reverse bias circuits, it is established that LEDs 4, 5, and 6 are ON, while LEDs 2 and 3 are OFF due to high resistance in reverse bias. The question arises regarding LED 1, which is connected in series with LEDs 2 and 3, and whether current can flow through it despite the reverse bias affecting the others. The clarification provided indicates that current cannot flow through LED 1 when LEDs 2 and 3 are OFF. Ultimately, the understanding is that all series-connected LEDs must conduct for current to flow, confirming that LED 1 is also OFF.
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Homework Statement


Indicate which of the 6 LEDs are ON and which are OFF


Homework Equations


V=IR


The Attempt at a Solution


Okay, I know LEDs 4,5 and 6 will be ON and LED 2 and 3 will be OFF but what about LED 1? Because LED 2 has a very high resistance as it is reverse biased thus no current flows, but would that mean current would still flow through LED 1?
 

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LED-s 1, 2, 3 are connected in series. Can the current flowing through LED 1 be different from the current which flows through the other ones?

ehild
 
oh i See! thankyou I understand now.
 
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