Length of Spring at Equilibrium: Find Solution with Mass, Length & Constant

  • Thread starter Thread starter FrozenWinters
  • Start date Start date
AI Thread Summary
The discussion centers on finding the equilibrium length of a suspended spring with mass m, length l, and spring constant k. The key equation involved is F = -kx + mg, where x represents the stretching of the spring. The challenge arises in solving the differential equation derived from this relationship, which some participants find unsolvable. A suggestion is made to refer to a specific physics forum for additional guidance on the problem. The conversation emphasizes the importance of correctly applying physics principles to determine the spring's length at equilibrium.
FrozenWinters
Messages
1
Reaction score
0
A spring of mass m, length l, and spring constant of k, is suspended. What is its length at equilibrium?

My current approach: look at the change in expansion relative to distance of the unexpanded spring. However, the differential equation I revive is unsolvable.
 
Physics news on Phys.org
F=-kx+mg...when does that equal 0? (This x gives the stretching)
 
FrozenWinters said:
My current approach: look at the change in expansion relative to distance of the unexpanded spring. However, the differential equation I revive is unsolvable.

That''s the right way to do it. See https://www.physicsforums.com/showthread.php?t=177689
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top