Lens equation: pretty simple probably

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To solve for the image distance and height using the lens equation, the setup is correct with 1/f = 1/do + 1/di. The next step involves subtracting 1/8.80 from 1/10.4 to find 1/di. Users are advised to utilize the 1/x function on their calculators to compute the fractions accurately. The final image distance will be negative, indicating the image is virtual, and the height should be calculated based on the magnification. Clear guidance is provided for those struggling with basic math calculations.
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Homework Statement



A converging lens ( f = 10.4 cm) is held 8.80 cm in front of a newspaper, the print size of which has a height of 2.04 mm. Find the image distance (in cm) and the height (in mm) of the magnified print.

D= _____cm
H= _____cm



Homework Equations



1/f=1/do+1/di

The Attempt at a Solution



1/10.4=1/8.80+1/di

I know this is the right setup but i feel like an idiot because I forget basic math...I don't remember how to solve this equation so if something can walk me through it step by step that would be great. I only have a simple scientific calculator that I keep using and get a decimal that isn't that right answer so i just don't know
 
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Hi johnson.3131! :smile:
johnson.3131 said:
1/10.4=1/8.80+1/di

I know this is the right setup but i feel like an idiot because I forget basic math...I don't remember how to solve this equation so if something can walk me through it step by step that would be great. I only have a simple scientific calculator that I keep using and get a decimal that isn't that right answer so i just don't know

Well, there's only two steps …subtract 1/8.80 from 1/10.4, and then 1/x it.

If you're getting it wrong, perhaps you'd better show us what you've done.

(you did remember the height is in mm, not cm?)
 
this is correct
1/10.4=1/8.80+1/di
so
1/10.4 - 1/8.8 = 1/di

Your calculator should have a 1/x function to calculate the two fractions on the left and subtract the answers. (The answer will be negative).
Then take that answer and use 1/x on it to get the value of di. (also negative)
 
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