Lens Formula Confusion: Convex Lens, Cartesian Sign Conv.

Click For Summary
SUMMARY

The discussion clarifies the Cartesian sign convention for convex lenses, emphasizing that distances along the principal axis are measured from the optical center. Positive distances are assigned to measurements in the direction of incident rays, while negative distances are assigned to the opposite direction. The lens equation, represented as 1/f = 1/v - 1/u, is applied to a scenario where the object is placed between 2f and f, leading to confusion regarding the signs of u and v. The participant acknowledges a mistake in their calculations, highlighting the importance of accurately applying the sign convention.

PREREQUISITES
  • Understanding of convex lens properties
  • Familiarity with the Cartesian sign convention
  • Knowledge of the lens formula 1/f = 1/v - 1/u
  • Ability to interpret ray diagrams
NEXT STEPS
  • Study the derivation of the lens formula for convex lenses
  • Learn how to construct ray diagrams for various object placements
  • Explore the implications of sign conventions in optics
  • Investigate real-world applications of convex lenses in optical devices
USEFUL FOR

Students of physics, optical engineers, and anyone seeking to deepen their understanding of lens behavior and sign conventions in optics.

anigeo
Messages
83
Reaction score
0
The cartesian sign convention for a convex lens is follows:
1. All distances on the principal axis are measured from the optical center.
2. The distances measured in the direction of incident rays are positive and all the distances measured in the direction opposite to that of the incident rays are negative.
3. All distances measured above the principal axis are positive. Thus, height of an object and that of an erect image are positive and all distances measured below the principal axis are negative.

Then for a convex lens when the object is placed between 2f and f,the image is formed between pole and f on the other side.
The lens equation is 1/f=1/v-1/u.
In this case,
v,f>0 and u<0.
then 1/u=1/v-1/f=(f-v)/(vb)>0,.....BUT HOW CAN THIS BE TRUE as u<0.
 
Science news on Phys.org
draw the ray diagram and notice that v > f
therefore, f-v < 0
which comes as no surprise because u < 0

what's the problem?
 
Thanks Simon,i just made a small mistake.
 
Happen to the best of us ;)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
11K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 58 ·
2
Replies
58
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K