Let a and b belong to Sn. Prove that (a^-1)(b^-1)(a)(b) is an even permutation.

  • Thread starter Thread starter tyrannical608
  • Start date Start date
  • Tags Tags
    even Permutation
tyrannical608
Messages
3
Reaction score
0

Homework Statement


Let a and b belong to Sn. Prove that (a^-1)(b^-1)(a)(b) is an even permutation.


Homework Equations


Definitions I have are
Every permutation in Sn, n>1 is a product of 2 cycles
and
A permutation that can be expressed as a product of an even number of 2 cycles is called an even permutation

Thanks
 
Physics news on Phys.org
So, it appears you are saying that all the permutations involved in a^{-1}b^{-1}ab is a two-cycle and this is a product of 4 of them!
 
HallsofIvy said:
So, it appears you are saying that all the permutations involved in a^{-1}b^{-1}ab is a two-cycle and this is a product of 4 of them!
Maybe its my flu...but what do you mean exactly? What I said are two definitions out of the book.

Do I have to show that a^-1b^-1 is one cycle and that ab is another cycle?
 
If a can be expressed as a product of k 2-cycles, what can you say about how many 2-cycles it takes to express a-1?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top