# Li atom and its valence e bound energy.

1. Dec 9, 2012

### prehisto

1. The problem statement, all variables and given/known data

Find bond energy of valence electron in principal state in Li atom 2S. If first line of the sharp series is 0.813microm and short wave boundary is 0.349 microm.

2. Relevant equations
i think I have to use $\tilde{v}$=R[( 1/(x-(Δ)) )^2-( 1/(n-(Δ)) )^2]
Δ-quantum defect,which mostly is Δ(l) and constants.
x- i dont now how this number is determined.

3. The attempt at a solution
So I have
1)atom of Li ; where l=0 and s=2.
2) line where "sharp" stands for s( here l too is l=0)
3) and some kind of boundary, i do not now what means "short wave boundary"

I suppose that short wave boundary has something to do with x in the boundary formula.
Could someone help me to make sense of all this,where should I start?

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