Light Bulbs Interference Pattern - Vey Easy Multiple Choice

AI Thread Summary
The discussion revolves around the conditions necessary for observing an interference pattern from two small light bulbs. The primary focus is on identifying why the interference pattern may not be visible, with options including random phase differences and short wavelengths. Participants suggest that random phase differences (option A) are the most significant factor, while also considering the impact of short wavelengths (option D). The consensus leans towards option A as the best answer, emphasizing the role of phase differences in light wave interference. Overall, the discussion highlights the complexities of light wave behavior in creating observable interference patterns.
rum2563
Messages
89
Reaction score
1

Homework Statement


Two small light bulbs are placed close together to try and create an interference pattern. This pattern would not be visible due to the:

a. random phase differences between the light waves from the two sources
b. very high speed of the light waves
c. diffraction of the light through the air molecules surrounding the bulbs
d. very short wavelengths of the light waves
e. inability of the human eyes to resolve two sources close together


Homework Equations





The Attempt at a Solution



I think the correct answer is A. But, D also sounds correct but I am not sure what is the best answer. I know that light has short wavelength but then two light sources also have random phase differences.

Please help.
 
Physics news on Phys.org
If the phase differences where really random, how could a shorter wavelength help you?
 
you are right... so i guess it is number A . Thanks.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top