- #1
Gogsey
- 153
- 0
Why don't we see interference of light from two light sources such as two candles? 2 reasons are required.
Thanks
Thanks
Light Interference: Why Don't We See 2 Sources? 2 Reasons
- Thread starter Gogsey
- Start date
AI Thread Summary
Light interference from two sources, such as candles, is not commonly observed due to specific conditions. The wavelength of the light plays a crucial role, as interference patterns require a certain relationship between the wavelengths of the sources. Additionally, the phase of the light waves must align appropriately for interference to occur. Without these conditions being met, the light from two sources does not produce noticeable interference patterns. Understanding these factors is essential to grasp why interference is not typically seen with everyday light sources.
- #2
VantagePoint72
- 820
- 34
I was all set to answer till you added "2 reasons are required"... it makes this sound suspiciously like a homework problem.
- #3
vincentchan
- 609
- 0
since this is a homework problem, i can't give you the answer..(you said 2 reasons are required) 
but i'll give you some hints lead to the answer
1. wavelength... in order for a interference exist... what is the restriction on the wavelength?
2. the phase of the light wave...
but i'll give you some hints lead to the answer1. wavelength... in order for a interference exist... what is the restriction on the wavelength?
2. the phase of the light wave...
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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