Light Speed Debate: Is It Possible to Travel Faster?

AI Thread Summary
The discussion centers on the possibility of traveling faster than light, challenging the notion that two objects moving away from each other at light speed could result in a relative speed greater than light. It emphasizes that the correct method for calculating relative speeds in relativity involves the Lorentz transformations, which ensure that no speed exceeds the speed of light (c). A specific example illustrates that even if two objects each travel at speed c, their relative speed remains c when calculated correctly. The conversation highlights the importance of understanding relativistic physics and the implications of speed addition in this context. Overall, the consensus reinforces that according to established physics, traveling faster than light is not feasible.
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Like we have learned in school, the ultimate speed is a light speed. Do you believe that? We may be wrong. Let's take an example. There are two objects. They start in the same place and they start moving away from each other. They are traveling in a speed of a light. But isn't the speed they are moving away from each other two times light speed.
v1 C v2
<---O-----*-----O--->
v1 is light of speed and v2 is light of speed. C is where they started. v1+v2 is two times light speed. It seems to me that the distant is growing two times LS. It means that its bigger than light speed.
 
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In relativity the formula for adding speeds is not the usual one. When you use that formula, derived from the Lorentz transformations, you never get the sum of speeds bigger than c.

The justification for the Lorentz transformations is hundreds of thousands of confirming experiments every day.
 
Or, just possibly, YOU may be wrong. In this particular case, you simply did the arithmetic wrong.

If object A is moving away from point B at speed v1 and object C is moving away from point B with speed v2 in exactly the opposite direction, then the speed of A relative to B is given by

\frac{v_1+v_2}{1+\frac{v_1v_2}{c^2}}.

It is easy to see that if v1and v2 are both less than c, then so is this value. In your specifice example, where v1 and v2 are both equal to c (the speed of each relative to B is c) then the speed of each relative to the other is \frac{2c}{1+ \frac{c^2}{c^2}}= \frac{2c}{2}= c.

The only objection I have with SelfAdjoint's response is the phrase "In relativity the formula for adding speeds is not the usual one.". It is not the approximation that we commonly use for adding very very low speeds!
 
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